tag:blogger.com,1999:blog-3846116389579818553.post2418012243505066853..comments2024-03-12T00:22:15.247-07:00Comments on HAMILTON MORRIS?: LIBERTIES AND HYDROGENHamilton Morrishttp://www.blogger.com/profile/16456180142284395836noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-3846116389579818553.post-92188353678168287082011-03-27T09:24:05.243-07:002011-03-27T09:24:05.243-07:00Time for an experiment!
Have two people play a ga...Time for an experiment!<br /><br />Have two people play a game of go. Establish a winner, and identify the various shapes your winner's pieces took, and assign them to similar carbon chain to see if they match up with stability. That should hold true since long chain alkanes have more stability than branched once, and Beavis just said the higher the stone to freedom ratio the better off you are).Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-3846116389579818553.post-9913748228107307492011-03-27T08:33:21.703-07:002011-03-27T08:33:21.703-07:00Hi Hamilton,
these analogies result from the simi...Hi Hamilton,<br /><br />these analogies result from the similarity of the graphs representing a go board and a carbon based molecule. The vertices on a go board got four edges and a carbon atom got four free electrons.<br />So, how does this topology "define the strength and influence of a go shape impact, say, the stability of a molecule".<br />There is one thumb rule in go which comes to my mind: It is favorable to have a high freedoms to stone ratio. <br />This is why three stones in I shape are better than a L shape, or ___ is better than _I_. The problem here with the analogy is, there is no analogy, corresponding molecules in the later cases don't exist. <br />Or could it work on a more abstract level, surface to volume ratio. How does this influence the stability of a molecule? <br /><br />Cheers<br /><br />GordianBeavishttps://www.blogger.com/profile/02725419320186923974noreply@blogger.com